I found this really simple recursive CTE useful for ensuring I understood how to write recursive CTEs.
with recursive counter(x) as (
select 0
union
select x + 1 from counter
)
select * from counter limit 5;This query returns five rows from a single column x - from 0 to 4.
| x |
|---|
| 0 |
| 1 |
| 2 |
| 3 |
| 4 |
If you write with recursive counter as ..., omitting the (x), you get the following error:
no such column: x
You can fix that by assigning x as the alias in the first part of that union:
with recursive counter as (
select 0 as x
union
select x + 1 from counter
)
select * from counter limit 5;So that counter(x) formulation is really just a way to define the column names up front.
This query returns two columns, x and y:
with recursive counter(x, y) as (
select 0 as x, 1 as y
union
select x + 1, y + 2 from counter
)
select * from counter limit 5;| x | y |
|---|---|
| 0 | 1 |
| 1 | 3 |
| 2 | 5 |
| 3 | 7 |
| 4 | 9 |
Created 2022-03-20T21:32:23-07:00, updated 2022-03-25T12:23:53-07:00 · History · Edit